16x^2-56x-96=4x^2

Solution for 16x^2-56x-96=4x^2 equation:

16x^2-56x-96=4x^2

We move all terms to the left:

16x^2-56x-96-(4x^2)=0

determiningTheFunctionDomain
16x^2-4x^2-56x-96=0

We add all the numbers together, and all the variables

12x^2-56x-96=0

a = 12; b = -56; c = -96;
Δ = b2-4ac
Δ = -562-4·12·(-96)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-88}{2*12}=\frac{-32}{24}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+88}{2*12}=\frac{144}{24}
=6
$